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The probability depends on how many decks are played. Of course the essential ingredients to blackjack are an ace and a One question.


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Conditional Probability (3 of 7: Analysing a deck of cards)

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A blackjack game has a dealer and one or more players. Let's call p the total probability of winning a pass line bet (so p is the number we are trying to calculate). Problems. If you are dealt a point total of 16, what is the probability of busting.


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The probability depends on how many decks are played. Of course the essential ingredients to blackjack are an ace and a One question.


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I have a few questions regarding blackjack: How often can one expect the dealer to bust and how often can a player expect to win four hands in a row? John from.


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Blackjack Expert Explains How Card Counting Works - WIRED

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Objective: Compute the probability of winning in several blackjack situations. Observe the Answers to hand-out questions: 1. answers.


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Typical questions to ask are to find the probabilities of winning for some of the to simple questions like: what is the probability of being dealt a blackjack (an.


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The probability depends on how many decks are played. Of course the essential ingredients to blackjack are an ace and a One question.


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21 - Monty Hall - PROPENSITY BASED THEORETICAL MODEL PROBABILITY - MATHEMATICS in the MOVIES

Viewed 19k times. Hot Network Questions. Mathematics Stack Exchange works best with JavaScript enabled.{/INSERTKEYS}{/PARAGRAPH} What posts should be escalated to staff using [status-review], and how do Iā€¦. Ross Millikan Ross Millikan k 24 24 gold badges silver badges bronze badges. Then for the other player we either give them two aces from the 3 that are left, give them one ace from the 3 that are left and 1 of the 32 cards, or give them two non-aces from the 47 non-aces that are left. Blackjack Probability Ask Question. We're switching to CommonMark. The probability of both getting blackjack is just the probability of the player getting blackjack and the subsequent probability of the dealer also getting blackjack:. Featured on Meta. I can't help but wonder if there perhaps is a less hideous way of acquiring the same answer though. Sign up to join this community. Home Questions Tags Users Unanswered. The outermost branches are short, but the inside of the tree is massive Hopefully this at least helps you contextualize the problem. With a branching factor of five I know , we have two aces, once ace, two whatevers, one 10, two 10s. Michael Cotton Michael Cotton 3 3 silver badges 6 6 bronze badges. So I deleted the more complicated answer I tried to give earlier. Active Oldest Votes. Asked 5 years, 3 months ago. This is not quite correct, as the fact that the first player did not get blackjack enriches the average deck with cards that could make a blackjack for the second player. Post as a guest Name. Sign up using Facebook. Sign up using Email and Password. Related 0. Nolohice 5 5 silver badges 12 12 bronze badges. Your calculation for the first player is correct. Question feed. The use of neither indicates that. The best answers are voted up and rise to the top. I don't know if this will get you any closer to a closed form solution, but maybe it helps you think about it. It only takes a minute to sign up. Suppose that you are playing blackjack against the dealer. {PARAGRAPH}{INSERTKEYS}Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Because the chance of one player getting blackjack is small, the enrichment is small as well, so this is not far off. Email Required, but never shown. Active 1 year, 7 months ago. MaxWell MaxWell 2 2 bronze badges. Sign up or log in Sign up using Google. The naive assumption is that the chance of each player getting blackjack is independent of the others. This happens every time.